Students Marks Sum - Hacker Rank Solution

Problem Statement

• The alternating elements marks0, marks2, marks4, and so on denote the marks of boys.
• Similarly, marks1, marks3, marks5, and so on denote the marks of girls.

• marks of boys if gender = b
• marks of girl if gender = g

Input Format

• The first line contains number_of_students, denoting the number of students in the class, hence the number of elements in marks.
• Each of the number_of_students subsequent lines contains marksi.
• The next line contains gender.

Constraints

•  number_of_students <=10^3
• 1<=marksi<=10^3 (where 0<= i< number_of_students)
•  gender = g or b

Sample Input 0

3
3
2
5
b

Sample Output 0

8

Explanation 0

Sample Input 1

5
1
2
3
4
5
g

Sample Output 1 

6

Explanation 1

Sample Input 2

1
5
g

Sample Output 2 

0

Explanation 2

Solution :-

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#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>

//Complete the following function.

int marks_summation(int* marks, int number_of_students, char gender) 
{
  //Write your code here.
  int sum = 0;
    for (int i = (gender == 'b' ? 0 : 1); i < number_of_students; i = i + 2) 
        sum += *(marks + i);
    
    return sum;
}
int main() {
    int number_of_students;
    char gender;
    int sum;
  
    scanf("%d", &number_of_students);
    int *marks = (int *) malloc(number_of_students * sizeof (int));
 
    for (int student = 0; student < number_of_students; student++) {
        scanf("%d", (marks + student));
    }
    
    scanf(" %c", &gender);
    sum = marks_summation(marks, number_of_students, gender);
    printf("%d", sum);
    free(marks);
 
    return 0;
}

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