Pointers in C - Hacker Rank Solution
Pointers in C - Hacker Rank Solution
Problem
Objective
In this challenge, you will learn to implement the basic functionalities of pointers in C. A pointer
in C is a way to share a memory address among different contexts
(primarily functions). They are primarily used whenever a function needs
to modify the content of a variable, of which it doesn't have
ownership.
In order to access the memory address of a variable,val, we need to prepend it with & sign. E.g.,
&val returns the memory address of val.
This memory address is assigned to a pointer and can be shared among various functions. E.g. int *p = &val will assign the memory address of val to pointer p. To access the content of the memory to which the pointer points, prepend it with a
*. For example, *p will return the value reflected by val and any modification to it will be reflected at the source (val).1 2 3 4 5 6 7 8 9 10 | void increment(int *v) { (*v)++; } int main() { int a; scanf("%d", &a); increment(&a); printf("%d", a); return 0; } |
Task
You have to complete the function
- a` = a+bvoid update(int *a,int *b), which reads two integers as argument, and sets a with the sum of them, and b with the absolute difference of them.- b` = |a-b|
Input Format
The input will contain two integers, a and b, separated by a newline.
Output Format
You have to print the updated value of a and b on two different lines.
Note: Input/ouput will be automatically handled. You only have to complete the function described in the 'task' section.
Solution :-
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 | // Pointers in C - Hacker Rank Solution #include <stdio.h> #include <stdlib.h> void update(int *a,int *b) { // Pointers in C - Hacker Rank Solution START int x,y; x = *a + *b; y = *a - *b; *a = x; *b =abs(y); // Pointers in C - Hacker Rank Solution END } int main() { int a, b; int *pa = &a, *pb = &b; scanf("%d %d", &a, &b); update(pa, pb); printf("%d\n%d", a, b); return 0; } |
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