Default Arguments in Python - HackerRank Solution
Default Arguments in Python - HackerRank Solution
Problem :
In this challenge, the task is to debug the existing code to successfully
execute all provided test files.
Python supports a useful concept of default argument values. For each keyword
argument of a function, we can assign a default value which is going to be
used as the value of said argument if the function is called without it. For
example, consider the following increment function:
def increment_by(n, increment=1): return n + increment
The functions works like this:
>>> increment_by(5, 2) 7 >>> increment_by(4) 5 >>>
The function has the following signature:
def print_from_stream(n, stream)
This function should print the first n values returned by get_next() method of
stream object provided as an argument. Each of these values should be printed
in a separate line.
Whenever the function is called without the stream argument, it should use an
instance of EvenStream class defined in the code stubs below as the value of
stream.
Your function will be tested on several cases by the locked template code.
Input Format :
The input is read by the provided locked code template. In the first line,
there is a single integer q denoting the number of queries. Each of the
following line q contains a stream_name followed by integer n, and it
corresponds to a single test for your function.
Constraints :
- 1 <= q <= 100
- 1 <= N <= 10
Output Format :
The output is produced by the provided and locked code template. For each of
the queries (stream_name, n), if the stream_name is even then
print_from_stream(n) is called. Otherwise, if the stream_name is odd, then
print_from_stream(n, OddStream()) is called.
Sample Input :
3 odd 2 even 3 odd 5
Sample Output :
1 3 0 2 4 1 3 5 7 9
Explanation :
There are 3 queries in the sample.
In the first query, the function print_from_stream(2, OddStream()) is
exectuted, which leads to printing values 1 and 3 in separated lines as the
first two non-negative odd numbers.
In the second query, the function print_from_stream(3) is exectuted, which
leads to printing values 2, 4 and 6 in separated lines as the first three
non-negative even numbers.
In the third query, the function print_from_stream(5, OddStream()) is
exectuted, which leads to printing values 1, 3, 5, 7 and 9 in separated lines
as the first five non-negative odd numbers.
Solution :
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 | # Default Arguments in Python - Hacker Rank Solution # Python 3 class EvenStream(object): def __init__(self): self.current = 0 def get_next(self): to_return = self.current self.current += 2 return to_return class OddStream(object): def __init__(self): self.current = 1 def get_next(self): to_return = self.current self.current += 2 return to_return # Default Arguments in Python - Hacker Rank Solution START -----> def print_from_stream(n, stream=None): if stream is None: stream = EvenStream() # Default Arguments in Python - Hacker Rank Solution END -----> for _ in range(n): print(stream.get_next()) queries = int(input()) for _ in range(queries): stream_name, n = input().split() n = int(n) if stream_name == "even": print_from_stream(n) else: print_from_stream(n, OddStream()) |
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