For Loop in C - Hacker Rank Solution
For Loop in C - Hacker Rank Solution
Problem
Objective
In this challenge, you will learn the usage of the for loop, which is a programming language statement which allows code to be repeatedly executed.The syntax for this is
for ( <expression_1> ; <expression_2> ; <expression_3> ) <statement>
- expression_1 is used for initializing variables which are generally used for controlling the terminating flag for the loop.
- expression_2 is used to check for the terminating condition. If this evaluates to false, then the loop is terminated.
- expression_3 is generally used to update the flags/variables
for(int i = 0; i < 10; i++) { ... }
Task
For each integer n in the interval [a,b] (given as input) :- If 1<= n , then print the English representation of it in lowercase. That is "one" for 1, "two" for 2, and so on.
- Else if n > 9 and it is an even number, then print "even".
- Else if n < 9 and it is an odd number, then print "odd".
Input Format
The first line contains an integer, a.
The second line contains an integer, b.
Constraints :-
1<=a<=b<=10^6Output Format
even, or odd, based on the conditions described in the 'task' section.Sample Input
8 11
Sample Output
eight nine even odd
Solution :-
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 | // For Loop in C - Hacker Rank Solution #include <stdio.h> #include <string.h> #include <math.h> #include <stdlib.h> int main() { int a, b; scanf("%d\n%d", &a, &b); // Complete the code. // For Loop in C - Hacker Rank Solution START char *str[] = {"one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "even", "odd"}; scanf("%d\n%d", &a, &b); for (int i=a; i<=b; i++)// i= 8 { if (i <= 9) { printf ("%s\n", str[i-1]); } else { printf ("%s\n", str[9+(i%2)]); } // For Loop in C - Hacker Rank Solution END } return 0; } |
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CodeWorld19
Hey, I am Parthe Omkar
why we use "char *str[]" here please tell me
Array of Pointers to strings
can we solve the question using switch case??
No bro you cant, because if you use switch case inside the for loop then each and every case will execute, this is not the case right ?