Validating UID in Python - HackerRank Solution
Validating UID in Python - HackerRank Solution
Problem :
ABCXYZ company has up to 100 employees.
The company decides to create a unique identification number (UID) for each of its employees.
The company has assigned you the task of validating all the randomly generated UIDs.
A valid UID must follow the rules below:
- It must contain at least 2 uppercase English alphabet characters.
- It must contain at least 3 digits ( 0 - 9).
- It should only contain alphanumeric characters ( a - z, A - Z & 0 - 9).
- No character should repeat.
- There must be exactly 10 characters in a valid UID.
Input Format :
The first line contains an integer T, the number of test cases.
The next T lines contains an employee's UID.
The next T lines contains an employee's UID.
Output Format :
For each test case, print 'Valid' if the UID is valid. Otherwise, print
'Invalid', on separate lines. Do not print the quotation marks.
Sample Input :
2
B1CD102354
B1CDEF2354
Sample Output :
Invalid Valid
Explanation :
B1CD102354: 1 is repeating → Invalid
B1CDEF2354: Valid
B1CDEF2354: Valid
Solution :
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 | # Validating UID in Python - Hacker Rank Solution # Python 3 # Validating UID in Python - Hacker Rank Solution START import re for i in range(int(input())): N = input().strip() if N.isalnum() and len(N) == 10: if bool(re.search(r'(.*[A-Z]){2,}',N)) and bool(re.search(r'(.*[0-9]){3,}',N)): if re.search(r'.*(.).*\1+.*',N): print('Invalid') else: print('Valid') else: print('Invalid') else: print('Invalid') # Validating UID in Python - Hacker Rank Solution END |
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