Re.findall() & Re.finditer() in Python - HackerRank Solution
Re.findall() & Re.finditer() in Python - HackerRank Solution
Problem :
re.findall()
The expression re.findall() returns all the non-overlapping matches of patterns in a string as a list of strings.
Code :
The expression re.findall() returns all the non-overlapping matches of patterns in a string as a list of strings.
Code :
>>> import re >>> re.findall(r'\w','http://www.hackerrank.com/') ['h', 't', 't', 'p', 'w', 'w', 'w', 'h', 'a', 'c', 'k', 'e', 'r', 'r', 'a', 'n', 'k', 'c', 'o', 'm']
Code :
>>> import re >>> re.finditer(r'\w','http://www.hackerrank.com/') <callable-iterator object at 0x0266C790> >>> map(lambda x: x.group(),re.finditer(r'\w','http://www.hackerrank.com/')) ['h', 't', 't', 'p', 'w', 'w', 'w', 'h', 'a', 'c', 'k', 'e', 'r', 'r', 'a', 'n', 'k', 'c', 'o', 'm']
Task :
You are given a string S. It consists of alphanumeric characters, spaces and symbols(+,-).Your task is to find all the substrings of S that contains 2 or more vowels.
Also, these substrings must lie in between 2 consonants and should contain vowels only.
Note :
Vowels are defined as: AEIOU and aeiou.
Consonants are defined as: QWRTYPSDFGHJKLZXCVBNM and qwrtypsdfghjklzxcvbnm.
Input Format :
A single line of input containing string S.Constraints :
- 0 < len(s)<100
Output Format :
Print the matched substrings in their order of occurrence on separate lines.If no match is found, print -1.
Sample Input :
>>> import re >>> re.finditer(r'\w','http://www.hackerrank.com/') <callable-iterator object at 0x0266C790> >>> map(lambda x: x.group(),re.finditer(r'\w','http://www.hackerrank.com/')) ['h', 't', 't', 'p', 'w', 'w', 'w', 'h', 'a', 'c', 'k', 'e', 'r', 'r', 'a', 'n', 'k', 'c', 'o', 'm']
Sample Output :
ee Ioo Oeo eeeee
Explanation :
ee is located between consonant d and f.Ioo is located between consonant k and m.
Oeo is located between consonant p and r.
eeeee is located between consonant t and t.
Solution :
1 2 3 4 5 6 7 8 9 10 11 12 13 14 | # Re.findall() & Re.finditer() in Python - Hacker Rank Solution # Python 3 # Enter your code here. Read input from STDIN. Print output to STDOUT # Re.findall() & Re.finditer() in Python - Hacker Rank Solution START import re Storage = re.findall(r'(?<=[qwrtypsdfghjklzxcvbnm])([aeiou]{2,})(?=[qwrtypsdfghjklzxcvbnm])', input().strip(), re.IGNORECASE) if Storage: for i in Storage: print(i) else: print(-1) # Re.findall() & Re.finditer() in Python - Hacker Rank Solution END |
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