Group() Groups() Groupdict() in Python - HackerRank Solution
Group() Groups() Groupdict() in Python - HackerRank Solution
Problem :
group()
A group() expression returns one or more subgroups of the match.
Code :
>>> import re >>> m = re.match(r'(\w+)@(\w+)\.(\w+)','username@hackerrank.com') >>> m.group(0) # The entire match 'username@hackerrank.com' >>> m.group(1) # The first parenthesized subgroup. 'username' >>> m.group(2) # The second parenthesized subgroup. 'hackerrank' >>> m.group(3) # The third parenthesized subgroup. 'com' >>> m.group(1,2,3) # Multiple arguments give us a tuple. ('username', 'hackerrank', 'com')
groups()
A groups() expression returns a tuple containing all the subgroups of the match.
Code :
>>> import re >>> m = re.match(r'(\w+)@(\w+)\.(\w+)','username@hackerrank.com') >>> m.groups() ('username', 'hackerrank', 'com')
groupdict()
A groupdict() expression returns a dictionary containing all the named subgroups of the match, keyed by the subgroup name.
Code :
>>> m = re.match(r'(?P<user>\w+)@(?P<website>\w+)\.(?P<extension>\w+)','myname@hackerrank.com') >>> m.groupdict() {'website': 'hackerrank', 'user': 'myname', 'extension': 'com'}
Task :
You are given a string S.Your task is to find the first occurrence of an alphanumeric character in S(read from left to right) that has consecutive repetitions.
Input Format :
A single line of input containing the string S.Constraints :
- 0 < len(S) < 100
Output Format :
Print the first occurrence of the repeating character. If there are no repeating characters, print -1.Sample Input :
..12345678910111213141516171820212223
Sample Output :
1
Explanation :
.. is the first repeating character, but it is not alphanumeric.1 is the first (from left to right) alphanumeric repeating character of the string in the substring 111.
Solution :
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 | # Group() Groups() Groupdict() in Python - Hacker Rank Solution # Python 3 # Enter your code here. Read input from STDIN. Print output to STDOUT # Group() Groups() Groupdict() in Python - Hacker Rank Solution START import re expression=r"([a-zA-Z0-9])\1+" m = re.search(expression,input()) if m: print(m.group(1)) else: print(-1) # Group() Groups() Groupdict() in Python - Hacker Rank Solution END |
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