Reduce Function in Python - HackerRank Solution
Reduce Function in Python - HackerRank Solution
Problem :
Given a list of rational numbers,find their product.
Concept :
The reduce() function applies a function of two arguments cumulatively on a
list of objects in succession from left to right to reduce it to one value.
Say you have a list, say [1,2,3] and you have to find its sum.
>>> reduce(lambda x, y : x + y,[1,2,3]) 6
You can also define an initial value. If it is specified, the function will
assume initial value as the value given, and then reduce. It is equivalent to
adding the initial value at the beginning of the list. For example:
>>> reduce(lambda x, y : x + y, [1,2,3], -3) 3 >>> from fractions import gcd >>> reduce(gcd, [2,4,8], 3) 1
Input Format :
The ith of next n lines contain two integers each, the numerator (Ni) and
denominator(Di) of the ith rational number in the list.
Constraints :
- 1 <= n <= 100
- 1 <= Ni, Di <= 10^9
Output Format :
Print only one line containing the numerator and denominator of the product of
the numbers in the list in its simplest form, i.e. numerator and denominator
have no common divisor other than 1.
Sample Input :
3 1 2 3 4 10 6
Sample Output :
5 8
Explanation :
Required product is 1/2 3/4 10/6 = 5/8
Solution :
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 | # Reduce Function in Python - Hacker Rank Solution # Python 3 from fractions import Fraction from functools import reduce def product(fracs): # Reduce Function in Python - Hacker Rank Solution START t = Fraction(reduce(lambda x, y: x * y, fracs)) # complete this line with a reduce statement # Reduce Function in Python - Hacker Rank Solution END return t.numerator, t.denominator if __name__ == '__main__': fracs = [] for _ in range(int(input())): fracs.append(Fraction(*map(int, input().split()))) result = product(fracs) print(*result) |
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