Regex Substitution in Python - HackerRank Solution
Regex Substitution in Python - HackerRank Solution
Problem :
The re.sub() tool (sub stands for substitution) evaluates a pattern and, for each valid match, it calls a method (or lambda).
The method is called for all matches and can be used to modify strings in different ways.
The re.sub() method returns the modified string as an output.
Learn more about re.sub()
Transformation of Strings
Code :
import re #Squaring numbers def square(match): number = int(match.group(0)) return str(number**2) print re.sub(r"\d+", square, "1 2 3 4 5 6 7 8 9")
Output :
1 4 9 16 25 36 49 64 81
Replacements in Strings :
Code :
import re html = """ <head> <title>HTML</title> </head> <object type="application/x-flash" data="your-file.swf" width="0" height="0"> <!-- <param name="movie" value="your-file.swf" /> --> <param name="quality" value="high"/> </object> """ print re.sub("(<!--.*?-->)", "", html) #remove comment
Output :
<head> <title>HTML</title> </head> <object type="application/x-flash" data="your-file.swf" width="0" height="0"> <param name="quality" value="high"/> </object>
Task :
You are given a text of N lines. The text contains && and || symbols.Your task is to modify those symbols to the following:
&& → and || → or
Input Format :
The first line contains the integer, N.The next N lines each contain a line of the text.
Constraints :
- 0 < N < 100
- Neither
&&nor||occur in the start or end of each line.
Output Format :
Output the modified text.Sample Input :
11 a = 1; b = input(); if a + b > 0 && a - b < 0: start() elif a*b > 10 || a/b < 1: stop() print set(list(a)) | set(list(b)) #Note do not change &&& or ||| or & or | #Only change those '&&' which have space on both sides. #Only change those '|| which have space on both sides.
Sample Output :
a = 1; b = input(); if a + b > 0 and a - b < 0: start() elif a*b > 10 or a/b < 1: stop() print set(list(a)) | set(list(b)) #Note do not change &&& or ||| or & or | #Only change those '&&' which have space on both sides. #Only change those '|| which have space on both sides.
Solution :
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 | # Regex Substitution in Python - Hacker Rank Solution # Python 3 # Enter your code here. Read input from STDIN. Print output to STDOUT # Regex Substitution in Python - Hacker Rank Solution START import re def change(match): if match.group(1) == '&&': return 'and' else: return 'or' for _ in range(int(input())): print(re.sub(r"(?<= )(\|\||&&)(?= )", change,input())) # Regex Substitution in Python - Hacker Rank Solution END |
Disclaimer :-
the above hole problem statement is given by hackerrank.com but the solution is generated by the codeworld19 authority if any of the query regarding this post or website fill the following contact form thank you.
CodeWorld19
Hey, I am Parthe Omkar