Word Order in python - HackerRank Solution
Word Order in python - HackerRank Solution
Problem :
Note: Each input line ends with a "\n" character.
Constraints :
- 1 <= n <= 10^5
All the words are composed of lowercase English letters only.
Input Format :
The next n lines each contain a word.
Output Format :
On the first line, output the number of distinct words from the input.
On the second line, output the number of occurrences for each distinct word
according to their appearance in the input.
Sample Input :
4
bcdef
abcdefg
bcde
bcdef
Sample Output :
3 2 1 1
Explanation :
There are 3 distinct words. Here, "bcdef" appears twice in the input at the
first and last positions. The other words appear once each. The order of the
first appearances are "bcdef", "abcdefg" and "bcde" which corresponds to the
output.
Solution :
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 | # Word Order in python - Hacker Rank Solution # Python 3 # Enter your code here. Read input from STDIN. Print output to STDOUT # Word Order in python - Hacker Rank Solution START import collections; N = int(input()) d = collections.OrderedDict() for i in range(N): word = input() if word in d: d[word] +=1 else: d[word] = 1 print(len(d)); for k,v in d.items(): print(v,end = " "); # Word Order in python - Hacker Rank Solution END |
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Hey, I am Parthe Omkar
This is not showing correct in nptel programming exam y
n = int(raw_input().strip())
counter = {}
words = []
for i in range(n):
word = raw_input().strip()
if word in counter:
counter[word] += 1
else:
counter[word] = 1
words.append(word)
print len(words)
print ' '.join([str(counter[word]) for word in words])
from collections import Counter
# The first line contains the integer n
n = int(input())
# The next n lines each contain a word
ip = []
for i in range(n):
ip.append(input())
# Counter returns dict contains (key as each word) and (value as total no of occurrence of a particular word)
ip_counter = Counter(ip)
# The number of distinct words from the input
print(len(ip_counter))
# The number of occurrences for each distinct word according to their appearance in the input.
for i in ip_counter.values():
print(i, end=' ')
from collections import Counter
n=int(input())
h=set()
r=[]
for i in range(n):
p=input()
r.append(p)
h.add(p)
a=Counter(r)
print(len(h))
print(" ".join(list(str(i) for i in a.values())))