Check Strict Superset in Python - HackerRank Solution
Problem :
You are given a set A and n other sets.
Your job is to find whether set A is a strict superset of each of the N sets.
Print True, if A is a strict superset of each of the N sets. Otherwise, print False.
A strict superset has at least one element that does not exist in its subset.
Set ([1, 3, 4]) is a strict superset of set ([1, 3]).
Set ([1, 3, 4]) is not a strict superset of set ([1, 3, 4]).
Set ([1, 3, 4]) is not a strict superset of set ([1, 3, 5]).
Input Format :
The second line contains integer n, the number of other sets.
The next n lines contains the space separated elements of the other sets.
Constraints :
- 0 < len(set(A)) < 501
- 0 < N < 21
- 0 < len(other set) < 101
Output Format :
Print True if set A is a strict superset of all other N sets. Otherwise, print
False.
Sample Input :
1 2 3 4 5 6 7 8 9 10 11 12 23 45 84 78 2 1 2 3 4 5 100 11 12
Sample Output :
False
Explanation :
Set A is the strict superset of the set ([1, 2, 3, 4, 5]) but not of the set
([100, 11, 12]) because 100 is not in set A. Hence, the output is False.
Solution :
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 | # Check Strict Superset in Python - Hacker Rank Solution # Python 3 # Enter your code here. Read input from STDIN. Print output to STDOUT # Check Strict Superset in Python - Hacker Rank Solution START storage = set(input().split()) N = int(input()) output = True for i in range(N): storage2 = set(input().split()) if not storage2.issubset(storage): output = False if len(storage2) >= len(storage): output = False print(output) # Check Strict Superset in Python - Hacker Rank Solution END |
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Hey, I am Parthe Omkar
A = set(map(int,input().split()))
n_b = int(input())
boo = set()
for i in range(n_b):
B = set(map(int,input().split()))
if A.intersection(B) == B:
boo.add("True")
else:
boo.add("False")
out_put = "False"
if out_put in boo:
print(out_put)
else:
print('True')