Set discard() remove() and pop() in Python - HackerRank Solution

CodeWorld19
2 Aug, 2020
1
Set discard() remove() and pop() in Python - HackerRank Solution
Set discard() remove() and pop() in Python - HackerRank Solution


Problem :


.remove(x)
This operation removes element x from the set.
If element x does not exist, it raises a KeyError.
The .remove(x) operation returns None.

Example :
>>> s = set([1, 2, 3, 4, 5, 6, 7, 8, 9])
>>> s.remove(5)
>>> print s
set([1, 2, 3, 4, 6, 7, 8, 9])
>>> print s.remove(4)
None
>>> print s
set([1, 2, 3, 6, 7, 8, 9])
>>> s.remove(0)
KeyError: 0

.discard(x)
This operation also removes element x from the set.
If element x does not exist, it does not raise a KeyError.
The .discard(x) operation returns None.

Example :
>>> s = set([1, 2, 3, 4, 5, 6, 7, 8, 9])
>>> s.discard(5)
>>> print s
set([1, 2, 3, 4, 6, 7, 8, 9])
>>> print s.discard(4)
None
>>> print s
set([1, 2, 3, 6, 7, 8, 9])
>>> s.discard(0)
>>> print s
set([1, 2, 3, 6, 7, 8, 9])

.pop()
This operation removes and return an arbitrary element from the set.
If there are no elements to remove, it raises a KeyError.

Example :
>>> s = set([1])
>>> print s.pop()
1
>>> print s
set([])
>>> print s.pop()
KeyError: pop from an empty set

Task :

You have a non-empty set s, and you have to execute N commands given in N lines.
The commands will be pop, remove and discard.


Input Format :

The first line contains integer n, the number of elements in the set s.
The second line contains n space separated elements of set s. All of the elements are non-negative integers, less than or equal to 9.
The third line contains integer N, the number of commands.
The next N lines contains either pop, remove and/or discard commands followed by their associated value.

Constraints :

  • 0 < n < 20
  • 0 < N < 20

Output Format :

Print the sum of the elements of set s on a single line.


Sample Input :

9
1 2 3 4 5 6 7 8 9
10
pop
remove 9
discard 9
discard 8
remove 7
pop 
discard 6
remove 5
pop 
discard 5

Sample Output :

4

Explanation :

After completing these 10 operations on the set, we get set([4]). Hence, the sum is 4.
Note: Convert the elements of set s to integers while you are assigning them. To ensure the proper input of the set, we have added the first two lines of code to the editor.


Solution :


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# Set discard() remove() and pop() in Python - Hacker Rank Solution
# Python 3
# Set discard() remove() and pop() in Python - Hacker Rank Solution START
n = int(input())
s = set(map(int,input().split()))
num = int(input())
for i in range(num):
    ip = input().split()
    if ip[0]=="remove":
        s.remove(int(ip[1]))
    elif ip[0]=="discard":
        s.discard(int(ip[1]))
    else :
        s.pop()
print(sum(list(s)))
# Set discard() remove() and pop() in Python - Hacker Rank Solution END




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1 Comments
  • Leonid Churakov
    Leonid Churakov Sunday, January 02, 2022

    number_of_elements = int(input())
    inserted_set = set(map(int, input().split()))
    number_of_operations = int(input())


    for _ in range(number_of_operations):
    command = input().split()
    if len(command) == 1:
    eval(f'inserted_set.{command[0]}()')
    elif len(command) == 2:
    eval(f'inserted_set.{command[0]}({command[1]})')
    print(sum(inserted_set))

    Reply
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