Strings in C++ - Hacker Rank Solution
Problem
C++ provides a nice alternative data type to manipulate strings, and the data type is conveniently called string. Some of its widely used features are the following:
Declaration:
string a = "abc";
Size:
int len = a.size();
Concatenate two strings:
string a = "abc"; string b = "def"; string c = a + b; // c = "abcdef".
Accessing i th element:
string s = "abc"; char c0 = s[0]; // c0 = 'a' char c1 = s[1]; // c1 = 'b' char c2 = s[2]; // c2 = 'c' s[0] = 'z'; // s = "zbc"
P.S.: We will use cin/cout to read/write a string.
Input Format
You are given two strings, a and b, separated by a new line. Each string will consist of lower case Latin characters ('a'-'z').
Output Format
In the first line print two space-separated integers, representing the length of a and b, respectively.
In the second line print the string produced by concatenating a and b(a+b).
In the third line print two strings separated by a space, a' and b'.a' and b' are the same as a and b, respectively, except that their first characters are swapped.
Sample Input :
abcd ef
Sample Output :
4 2 abcdef ebcd af
Explanation :
- a = "abcd"
- b = "ef"
- |a| = 4
- |b| = 2
- a+b = "abcdef"
- a' = "ebcd"
- b' = "af"
Solution :-
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 | #include <iostream> #include <string> using namespace std; int main() { string str1,str2,str3; char b,a; int strlen1,strlen2; //string one cin>>str1; //string two cin>>str2; //first string size strlen1 = str1.size(); //second string size strlen2 = str2.size(); cout<<strlen1; cout<<" "<<strlen2; // concatinate two string str3 = str1+str2; cout<<"\n"<<str3; // a' b' a = str2[0]; b = str1[0]; str1[0] = a; str2[0] = b; cout<<"\n"; cout<<str1; cout<<" "<<str2; return 0; } |
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