Sorting Array of Strings - Hacker Rank Solution

CodeWorld19

15 May, 2020

Problem

To sort a given array of strings into lexicographically increasing order or into an order in which the string with the lowest length appears first, a sorting function with a flag indicating the type of comparison strategy can be written. The disadvantage with doing so is having to rewrite the function for every new comparison strategy.

A better implementation would be to write a sorting function that accepts a pointer to the function that compares each pair of strings. Doing this will mean only passing a pointer to the sorting function with every new comparison strategy.

Given an array of strings, you need to implement a string_sort function which sorts the strings according to a comparison function, i.e, you need to implement the function :

void string_sort(const char **arr,const int cnt, int (*cmp_func)(const char* a, const char* b)){
    
}

The arguments passed to this function are:

an array of strings : arr
length of string array: count
pointer to the string comparison function:cmp_func

You also need to implement the following four string comparison functions:

int lexicographic_sort(const char*, const char*) to sort the strings in lexicographically non-decreasing order.
int lexicographic_sort_reverse(const char*, const char*) to sort the strings in lexicographically non-increasing order.
int sort_by_number_of_distinct_characters(const char*, const char*) to sort the strings in non-decreasing order of the number of distinct characters present in them. If two strings have the same number of distinct characters present in them, then the lexicographically smaller string should appear first.
int sort_by_length(const char* a, const char* b) to sort the strings in non-decreasing order of their lengths. If two strings have the same length, then the lexicographically smaller string should appear first.

Input Format :

You just need to complete the function string\_sort and implement the four string comparison functions.

Constraints :

1<= No. of Strings <= 50
1<= Total length of all the Strings <=2500
You have to write your own sorting function and you cannot use the inbuilt qsort function
The strings consists of lower-case English Alphabets only.

Output Format :

The locked code-stub will check the logic of your code. The output consists of the strings sorted according to the four comparsion functions in the order mentioned in the problem statement.

Sample Input 0 :

4
wkue
qoi
sbv
fekls

Sample Output 0 :

fekls
qoi
sbv
wkue

wkue
sbv
qoi
fekls

qoi
sbv
wkue
fekls

qoi
sbv
wkue
fekls

Solution :

//Sorting Array of Strings - Hacker Rank Solution
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int lexicographic_sort(const char* a, const char* b)
{
    return strcmp(a, b);
}

int lexicographic_sort_reverse(const char* a, const char* b)
{
    return strcmp(b, a);
}
int characters_count(const char *s)
{
    int n = 0;
    int count[128] = {0};
    if (NULL == s)
    {
        return -1;
    }
    while(*s != '\0')
    {
        if (!count[*s])
        {
            count[*s]++;
            n++;
        }
        s++;
    }
    return n;
}

int sort_by_number_of_distinct_characters(const char* a, const char* b)
{
    int con = characters_count(a) - characters_count(b);
    return (con ? con : lexicographic_sort(a, b));
}

int sort_by_length(const char* a, const char* b) 
{
    int len = strlen(a) - strlen(b);
    return (len ? len : lexicographic_sort(a, b));
}

void string_sort(char** arr,const int len,int (*cmp_func)(const char* a, const char* b))
{
    int mid = len / 2;
    int con = 0;
    while(!con)
    {
        con = 1;
        for(int i = 0; i < len - 1; i++)
        {
            if(cmp_func(arr[i], arr[i + 1]) > 0) 
            {
                char *temp = arr[i];
                arr[i] = arr[i + 1];
                arr[i + 1] = temp;
                con = 0;
            }
        }
    }
}


int main() 
{
    int n;
    scanf("%d", &n);
  
    char** arr;
	arr = (char**)malloc(n * sizeof(char*));
  
    for(int i = 0; i < n; i++)
    {
        *(arr + i) = malloc(1024 * sizeof(char));
        scanf("%s", *(arr + i));
        *(arr + i) = realloc(*(arr + i), strlen(*(arr + i)) + 1);
    }
  
    string_sort(arr, n, lexicographic_sort);
    for(int i = 0; i < n; i++)
        printf("%s\n", arr[i]);
    printf("\n");

    string_sort(arr, n, lexicographic_sort_reverse);
    for(int i = 0; i < n; i++)
        printf("%s\n", arr[i]); 
    printf("\n");

    string_sort(arr, n, sort_by_length);
    for(int i = 0; i < n; i++)
        printf("%s\n", arr[i]);    
    printf("\n");

    string_sort(arr, n, sort_by_number_of_distinct_characters);
    for(int i = 0; i < n; i++)
        printf("%s\n", arr[i]); 
    printf("\n");
}

Disclaimer :-

the above whole problem statement is given by hackerrank.com but the solution is generated by the codeworld19 authority if any of the query regarding this post or website fill the following contact form thank you.

CodeWorld19

Hey, I am Parthe Omkar

Srujan Tuesday, May 18, 2021

olution.c: In function ‘characters_count’:
Solution.c:25:19: warning: array subscript has type ‘char’ [-Wchar-subscripts]
if (!count[*s])
^
Solution.c:27:18: warning: array subscript has type ‘char’ [-Wchar-subscripts]
count[*s]++;
^
Solution.c: In function ‘string_sort’:
Solution.c:49:7: warning: unused variable ‘mid’ [-Wunused-variable]
int mid = len / 2;
^~~
Solution.c: At top level:
Solution.c:107:5: error: redefinition of ‘main’
int main()
^~~~
Solution.c:68:5: note: previous definition of ‘main’ was here
int main()
^~~~
Exit Status

1

Sorting Array of Strings - Hacker Rank Solution

Problem

Input Format :

Constraints :

Output Format :

Sample Input 0 :

Sample Output 0 :

Solution :

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