For Loop in C++ - Hacker Rank Solution

Problem

Objectives

for ( <expression_1> ; <expression_2> ; <expression_3> )
    <statement>

• expression_1 is used for intializing variables which are generally used for controlling terminating flag for the loop.
• expression_2 is used to check for the terminating condition. If this evaluates to false, then the loop is terminated.
• expression_3 is generally used to update the flags/variables.
• A sample loop will be

for(int i = 0; i < 10; i++) {
    ...
}

Input Format

Output Format

• If 1<=n<=9 then print the English representation of it in lowercase. That is "one" for 1, "two" for 2, and so on.
• Else if n>9 and it is an even number, then print "even".
• Else if n>9 and it is an odd number, then print "odd".

Sample Input

8
11

Sample Output

eight
nine
even
odd

Solution :-

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#include <iostream>
#include <cstdio>
using namespace std;

int main() {
    // Complete the code.
    int a,b,i;
    char *str[] = {"one","two","three","four","five","six","seven","eight","nine","even","odd"};
    cin>>a;
    cin>>b;
    for(i=a;i<=b;i++)
    {
        if(i<=9)
        {
            cout<<str[i-1]<<"\n";
        }
        else
        {
            cout<<str[9+(i%2)]<<"\n";
        }
    }
    return 0;
}

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