Lower Bound-STL in C++ - Hacker Rank Solution
Problem
You are given N integers in sorted order. Also, you are given
Q queries. In each query, you will be given an integer and you have to tell
whether that integer is present in the array. If so, you have to tell at which
index it is present and if it is not present, you have to tell the index at
which the smallest integer that is just greater than the given number is
present. Lower bound is a function that can be used with a sorted vector. Learn
how to use lower bound to solve this problem by
Input Format :
The first line of the input contains the number of integers N. The next line
contains N integers in sorted order. The next line contains Q, the number of
queries. Then Q lines follow each containing a single integer Y.
Note that if the same number is present multiple times, you have to print the
first index at which it occurs. Also, the input is such that you always have an
answer for each query.
Constraints :
- 1 <= N <= 10^5
- 1 <= Xi <= 10^9, where Xi is ith element in the array.
- 1 <= Q <= 10^5
- 1 <= Y <= 10^9
Output Format :
For each query
you have to print "Yes" (without the quotes) if the number is present and at
which index(1-based) it is present separated by a space.
If the number is not present you have to print "No" (without the quotes) followed by the index of the next smallest number just greater than that number.
You have to output each query in a new line.
If the number is not present you have to print "No" (without the quotes) followed by the index of the next smallest number just greater than that number.
You have to output each query in a new line.
Sample Input :
8 1 1 2 2 6 9 9 15 4 1 4 9 15
Sample Output :
Yes 1 No 5 Yes 6 Yes 8
Solution :
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 |
//Lower Bound-STL in C++ - Hacker Rank Solution #include <cmath> #include <cstdio> #include <vector> #include <iostream> #include <algorithm> using namespace std; int main() { /* Enter your code here. Read input from STDIN. Print output to STDOUT */ /* Lower Bound-STL in C++ - Hacker Rank Solution START */ int m, n, num, i, val; cin >>m; vector <int> v(m); for(i = 0; i < m; i++) cin >> v[i]; cin>>n; for(i = 0; i < n; i++) { cin >> val; vector <int>::iterator low = lower_bound(v.begin(), v.end(), val); if (v[low - v.begin()] == val) { cout << "Yes " << (low - v.begin() + 1) << endl; } else { cout << "No " << (low - v.begin() + 1) << endl; } } /* Lower Bound-STL in C++ - Hacker Rank Solution END */ return 0; } |
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