Java Stdin and Stdout II in Java - Hacker Rank Solution
Problem
In this challenge, you must read an integer, a double, and a String from stdin, then print the values according to the instructions in the Output Format section below. To make the problem a little easier, a portion of the code is provided for you in the editor.
Note: We recommend completing Java Stdin and Stdout I before attempting this challenge.
Input Format
There are three lines of input:
- The first line contains an integer.
- The second line contains a double.
- The third line contains a String.
Output Format
There are three lines of output:
- On the first line, print
String:followed by the unaltered String read from stdin. - On the second line, print
Double:followed by the unaltered double read from stdin. - On the third line, print
Int:followed by the unaltered integer read from stdin.
To make the problem easier, a portion of the code is already provided in the editor.
Note: If you use the nextLine() method immediately following the nextInt() method, recall that nextInt()
reads integer tokens; because of this, the last newline character for
that line of integer input is still queued in the input buffer and the
next nextLine() will be reading the remainder of the integer line (which is empty).
Sample Input
42 3.1415 Welcome to HackerRank's Java tutorials!
Sample Output
String: Welcome to HackerRank's Java tutorials! Double: 3.1415 Int: 42
Solution :-
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 | import java.util.Scanner; public class Solution { public static void main(String[] args) { Scanner scan = new Scanner(System.in); int i = scan.nextInt(); double d = scan.nextDouble(); String s=""; while(scan.hasNext()) { s=scan.nextLine(); } System.out.println("String: " + s); System.out.println("Double: " + d); System.out.println("Int: " + i); } } |
CodeWorld19
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