Conditional Statements in C++ - Hacker Rank Solution
Problem
if and else are two of the most frequently used conditionals in C/C++, and they enable you to execute zero or one conditional statement among many such dependent conditional statements. We use them in the following ways:
1. if: This executes the body of bracketed code starting with statement1 if condition evaluates to true.
if (condition) {
statement1;
...
}
2. if - else: This executes the body of bracketed code starting with statement1 if condition evaluates to true, or it executes the body of code starting with statement2 if condition evaluates to false. Note that only one of the bracketed code sections will ever be executed.
if (condition) { statement1; ... } else { statement2; ... }
3. if - else if - else: In this structure, dependent statements are chained together and the condition or each statement is only checked if all prior conditions in the chain evaluated to false. Once a condition evaluates to true, the bracketed code associated with that
statement is executed and the program then skips to the end of the chain
of statements and continues executing. If each condition in the chain evaluates to false, then the body of bracketed code in the else block at the end is executed.
if(first condition) { ... } else if(second condition) { ... } . . . else if((n-1)'th condition) { .... } else { ... }
Given a positive integer denoting n, do the following:
- If 1<=n<=9, then print the lowercase English word corresponding to the number(e.g one for 1, two for 2 etc)
- if n > 9 Then print Greater than 9
Input Format
A single integer denoting n.Constraints
- 1<=n<=10^9
Output Format
If 1<=n<=9, then print the lowercase English word corresponding to the number(e.g one for 1, two for 2 etc), if n > 9 Then print Greater than 9.
Example 0 :
Sample Input 05
Sample Output 0
five
Explanation 0
five is the English word for the number 5.
Example 1 :
Sample Input 18
Sample Output 1
eight
Explanation 1
eight is the English word for the number 8.
Example 2 :
Sample Input 2
44
Sample Output 2
Greater than 9
Explanation 2
n = 44 is greater than 9, so we print Greater than 9.
Solution :
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 | #include <bits/stdc++.h> using namespace std; int main() { int n; cin >> n; cin.ignore(numeric_limits<streamsize>::max(), '\n'); // Write Your Code Here if (n==1) cout<<"one"; else if(n==2) cout<<"two"; else if(n==3) cout<<"three"; else if(n==4) cout<<"four"; else if(n==5) cout<<"five"; else if(n==6) cout<<"six"; else if(n==7) cout<<"seven"; else if(n==8) cout<<"eight"; else if(n==9) cout<<"nine"; else cout<<"Greater than 9"; return 0; } |
Disclaimer :-
the hole problem statement are given by HackerRank.com but the solution are generated by the codeworld19 authority if any of the query regarding this post or website fill the following contact form thank you.
the code is wrong