Basic Data Types in C++ - Hacker Rank Solution
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| Basic Data Types in C++ - Hacker Rank Solution |
Problem
Some C++ data types, their format specifiers, and their most common bit widths are as follows:
- Int ("%d"): 32 Bit integer
- Long ("%ld"): 64 bit integer
- Char ("%c"): Character type
- Float ("%f"): 32 bit real value
- Double ("%lf"): 64 bit real value
Reading
To read a data type, use the following syntax:scanf("`format_specifier`", &val);
For example, to read a character followed by a double:
char ch; double d; scanf("%c %lf", &ch, &d);
For the moment, we can ignore the spacing between format specifiers.
Printing
To print a data type, use the following syntax:printf("`format_specifier`", val);
For example, to print a character followed by a double:
char ch = 'd'; double d = 234.432; printf("%c %lf", ch, d);
Note: You can also use cin and cout instead of scanf and printf; however, if you are taking a million numbers as input and printing a million lines, it is faster to use scanf and printf.
Input Format
Input consists of the following space-separated values: int, long, char, float, and double, respectively.Output Format
Print each element on a new line in the same order it was received as input. Note that the floating point value should be correct up to 3 decimal places and the double to 9 decimal places.Sample Input :
3 12345678912345 a 334.23 14049.30493
Sample Output :
3 12345678912345 a 334.230 14049.304930000
Explanation :
Print int 3.followed by long 12345678912345.
followed by char a.
followed by float 334.230.
followed by double 14049.304930000.
Solution :
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 | #include <iostream> #include <cstdio> using namespace std; int main() { // Complete the code. int a; long long int b; char c; float d; double e; scanf("%d %lld %c %f %lf",&a,&b,&c,&d,&e); printf("%d\n%lld\n%c\n%f\n%lf",a,b,c,d,e); return 0; } |
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CodeWorld19
Hey, I am Parthe Omkar
not correct i think so
But, its c++ ,is it correct to write input and output statement of C language???
#include
#include
using namespace std;
int main() {
// Complete the code.
int a;
long b;
char c;
float d;
double e;
cin>>a>>b>>c>>d>>e;
cout<<a<<endl<<b<<endl<<c<<endl;
cout.precision(3);
cout<<fixed<<d<<endl;
cout.precision(9);
cout<<fixed<<e<<endl;
return 0;
}
#include
#include
#include
using namespace std;
int main() {
int a;
long b;
char c;
float d;
double e;
cin >> a >> b >> c >> d >> e;
cout<< a << '\n' << b << '\n' << c << '\n';
cout << std::fixed << std::setprecision(3) << d << '\n';
cout << std::fixed << std::setprecision(9) << e << '\n';
return 0;
}
#include
using namespace std;
int main() {
int a;
long b;
char c;
float d;
double e;
cin >> a >> b >> c >> d >> e;
cout<< a << '\n' << b << '\n' << c << '\n';
cout << std::fixed << std::setprecision(3) << d << '\n';
cout << std::fixed << std::setprecision(9) << e << '\n';
return 0;
}
//techdark.in
#include
#include
using namespace std;
int main() {
int a;
long long int b;
char c;
float s;
double d ;
scanf("%d %lld %c %f %lf",&a,&b,&c,&s,&d);
printf("%d\n%lld\n%c\n%f\n%lf",a,b,c,s,d);
return 0;
}
Plz can anyone tell me why float and double value showes 5 decimal points respectively when we don't use long long int but instead use only long
My Test case 0 was pass but another cases are fail, what is the problem?
#include
#include
using namespace std;
int main() {
int a;
long b;
char c;
float d;
double e;
cin>>a>>b>>c>>d>>e;
cout<<a<<endl<<b<<endl<<c<<endl<<d<<endl<<e<<endl;
return 0;
}
this is not write ans for all test case
exactly
same my test case 0 is pass but 1,2,3 are not pass