Java Datatypes - HackerRank Solution

CodeWorld19
7 Apr, 2021

Java Datatypes - HackerRank Solution
 
 Java Datatypes - HackerRank Solution
 

Problem :


Java has 8 primitive data types; char, boolean, byte, short, int, long, float, and double. For this exercise, we'll work with the primitives used to hold integer values (byte, short, int, and long):

• A byte is an 8-bit signed integer.
• A short is a 16-bit signed integer.
• An int is a 32-bit signed Integer.
• A long is a 64-bit signed integer.

Given an input integer, you must determine which primitive data types are capable of properly storing that input. To get you started, a portion of the solution is provided for you in the editor.
Reference: here

Input Format :-

The first line contains an integer, T, denoting the number of test cases. Each test case, T, is comprised of a single line with an integer, n, which can be arbitrarily large or small.

Output Format :-

For each input variable n and appropriate primitive dataType, you must determine if the given primitives are capable of
storing it. If yes, then print:
n can be fitted in:
* dataType
If there is more than one appropriate data type, print each one on its own line and order them by size (1.e.:
byte < short < int < long).
If the number cannot be stored in one of the four aforementioned primitives, print the line:
n can't be fitted anywhere.

Sample Input :-

5
-150
150000
1500000000
213333333333333333333333333333333333
-100000000000000

Sample Output :-

-150 can be fitted in:
* short
* int
* long
150000 can be fitted in:
* int
* long
1500000000 can be fitted in:
* int
* long
213333333333333333333333333333333333 can't be fitted anywhere.
-100000000000000 can be fitted in:
* long

Explanation :-

- 150 can be stored in a short, an int, or a long.
213333333333333333333333333333333333 is very large and is outside of the allowable range of values for the primitive data types discussed in this problem.
 

Solution :

Solution 1 :

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// Java Datatypes - HackerRank Solution
import java.util.*;
import java.io.*;

class Solution{
    public static void main(String []argh)
    {

        Scanner sc = new Scanner(System.in);
        int t=sc.nextInt();

        for(int i=0;i<t;i++)
        {

            try
            {
                long x = sc.nextLong();
                
                // Java Datatypes - HackerRank Solution START
                
                System.out.println(x+" can be fitted in:");
                if(x>=-128 && x<=127)
                {
                    System.out.println("* byte");
                }
                if(x>=-32768 && x<=32767)
                {
                    System.out.println("* short");
                }
                if(x>=-2147483648 && x<=2147483647)
                {
                    System.out.println("* int");
                }
                System.out.println("* long");
                
                // Java Datatypes - HackerRank Solution END
            }
            catch(Exception e)
            {
                System.out.println(sc.next()+" can't be fitted anywhere.");
            }

        }
    }
}
 

Solution 2 :

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// Java Datatypes - HackerRank Solution
import java.util.*;
import java.io.*;

class Solution{
    public static void main(String []argh)
    {

        Scanner sc = new Scanner(System.in);
        int t=sc.nextInt();

        for(int i=0;i<t;i++)
        {

            try
            {
                long x = sc.nextLong();
                
                System.out.println(x+" can be fitted in:");

                // Java Datatypes - HackerRank Solution START

                if(x>=(Byte.MIN_VALUE) && x<=Byte.MAX_VALUE)
                {
                    System.out.println("* byte");
                }
                if(x>=(Short.MIN_VALUE) && x<=Short.MAX_VALUE)
                {
                    System.out.println("* short");
                }
                if(x>=(Integer.MIN_VALUE) && x<=Integer.MAX_VALUE)
                {
                    System.out.println("* int");
                }
                if(x>=(Long.MIN_VALUE) && x<=Long.MAX_VALUE)
                {
                    System.out.println("* long");
                }

                // Java Datatypes - HackerRank Solution END
            }
            catch(Exception e)
            {
                System.out.println(sc.next()+" can't be fitted anywhere.");
            }

        }
    }
}
 

Solution 3 : 

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// Java Datatypes - HackerRank Solution
import java.util.*;
import java.io.*;
//Java Datatypes - HackerRank Solution solution you must declare the following package
import java.math.BigInteger;

class Solution{
    public static void main(String []argh)
    {

        Scanner sc = new Scanner(System.in);
        int t=sc.nextInt();

        for(int i=0;i<t;i++)
        {

            try
            {
                long x = sc.nextLong();
                BigInteger b = BigInteger.valueOf(x);
                System.out.println(x+" can be fitted in:");

                // Java Datatypes - HackerRank Solution START

                if(b.longValue()>=-128 && x<=127)
                {
                    System.out.println("* byte");
                }
                if(b.longValue()>=-(Math.pow(2,15)) && b.longValue()<=(Math.pow(2,15)-1))
                {
                    System.out.println("* short");
                }
                if(b.longValue()>=-(Math.pow(2,31)) && b.longValue()<=Math.pow(2,31)-1)
                {
                    System.out.println("* int");
                }
                if(b.longValue()>=-(Math.pow(2,63)) && b.longValue()<=Math.pow(2,63)-1)
                {
                    System.out.println("* long");
                }

                // Java Datatypes - HackerRank Solution END
            }
            catch(Exception e)
            {
                System.out.println(sc.next()+" can't be fitted anywhere.");
            }

        }
    }
}



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