Eye and Identity in Python - HackerRank Solution
Eye and Identity in Python - HackerRank Solution
Problem :
identity :
The identity tool returns an identity array. An identity array is a square
matrix with all the main diagonal elements as 1 and the rest as 0. The default
type of elements is float.
import numpy print numpy.identity(3) #3 is for dimension 3 X 3 #Output [[ 1. 0. 0.] [ 0. 1. 0.] [ 0. 0. 1.]]
eye :
The eye tool returns a 2-D array with 1's as the diagonal and 0's elsewhere.
The diagonal can be main, upper or lower depending on the optional parameter
K. A positive K is for the upper diagonal, a negative K is for the lower, and
a 0 K (default) is for the main diagonal.
import numpy print numpy.eye(8, 7, k = 1) # 8 X 7 Dimensional array with first upper diagonal 1. #Output [[ 0. 1. 0. 0. 0. 0. 0.] [ 0. 0. 1. 0. 0. 0. 0.] [ 0. 0. 0. 1. 0. 0. 0.] [ 0. 0. 0. 0. 1. 0. 0.] [ 0. 0. 0. 0. 0. 1. 0.] [ 0. 0. 0. 0. 0. 0. 1.] [ 0. 0. 0. 0. 0. 0. 0.] [ 0. 0. 0. 0. 0. 0. 0.]] print numpy.eye(8, 7, k = -2) # 8 X 7 Dimensional array with second lower diagonal 1.
Task :
Your task is to print an array of size N*M with its main diagonal elements as
1's and 0's everywhere else.
Input Format :
A single line containing the space separated values of N and M.
N denotes the rows.
M denotes the columns.
Output Format :
Print the desired N*M array.
Sample Input :
3 3
Sample Output :
[[ 1. 0. 0.] [ 0. 1. 0.] [ 0. 0. 1.]]
Solution :
1 2 3 4 5 6 7 8 | # Eye and Identity in Python - Hacker Rank Solution # Python 3 # Eye and Identity in Python - Hacker Rank Solution START import numpy numpy.set_printoptions(sign=' ') print(numpy.eye(*map(int, input().split()))) # Eye and Identity in Python - Hacker Rank Solution END |
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