Decorators 2 - Name Directory in Python - HackerRank Solution
Decorators 2 - Name Directory in Python - HackerRank Solution
Problem :
Let's use decorators to build a name directory! You are given some information
about N people. Each person has a first name, last name, age and sex. Print
their names in a specific format sorted by their age in ascending order i.e.
the youngest person's name should be printed first. For two people of the same
age, print them in the order of their input.
For Henry Davids, the output should be:
Mr. Henry Davids
For Mary George, the output should be:
Ms. Mary George
Input Format :
The first line contains the integer N, the number of people.
N lines follow each containing the space separated values of the first name,
last name, age and sex, respectively.
Constraints :
- 0 <= N <= 10
Output Format :
Output N names on separate lines in the format described above in ascending
order of age.
Sample Input :
3 Mike Thomson 20 M Robert Bustle 32 M Andria Bustle 30 F
Sample Output :
Mr. Mike Thomson Ms. Andria Bustle Mr. Robert Bustle
Concept :
For sorting a nested list based on some parameter, you can use the itemgetter
library. You can read more about it
here.
Solution :
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 | # Decorators 2 - Name Directory in Python - Hacker Rank Solution # Python 3 import operator def person_lister(f): def inner(people): # Decorators 2 - Name Directory in Python - Hacker Rank Solution START # complete the function return map(f, sorted(people, key=lambda x: int(x[2]))) # Decorators 2 - Name Directory in Python - Hacker Rank Solution END return inner @person_lister def name_format(person): return ("Mr. " if person[3] == "M" else "Ms. ") + person[0] + " " + person[1] if __name__ == '__main__': people = [input().split() for i in range(int(input()))] print(*name_format(people), sep='\n') |
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