String Validators in Python - HackerRank Solution

CodeWorld19
19 Jul, 2020
7
String Validators in Python - HackerRank Solution
String Validators in Python - HackerRank Solution

Problem :


Python has built-in string validation methods for basic data. It can check if a string is composed of alphabetical characters, alphanumeric characters, digits, etc.

str.isalnum()
This method checks if all the characters of a string are alphanumeric (a-z, A-Z and 0-9).
>>> print 'ab123'.isalnum()
True
>>> print 'ab123#'.isalnum()
False

This method checks if all the characters of a string are alphabetical (a-z and A-Z).
>>> print 'abcD'.isalpha()
True
>>> print 'abcd1'.isalpha()
False

This method checks if all the characters of a string are digits (0-9).
>>> print '1234'.isdigit()
True
>>> print '123edsd'.isdigit()
False

str.islower()
This method checks if all the characters of a string are lowercase characters (a-z).
>>> print 'abcd123#'.islower()
True
>>> print 'Abcd123#'.islower()
False

This method checks if all the characters of a string are uppercase characters (A-Z).
>>> print 'ABCD123#'.isupper()
True
>>> print 'Abcd123#'.isupper()
False

Task :

You are given a string S.
Your task is to find out if the string S contains: alphanumeric characters, alphabetical characters, digits, lowercase and uppercase characters.


Input Format :

A single line containing a string S.

Constraints :

  • 0 <= len(s) <= 1000

Output Format :

In the first line, print True if S has any alphanumeric characters. Otherwise, print False.
In the second line, print True if S has any alphabetical characters. Otherwise, print False.
In the third line, print True if S has any digits. Otherwise, print False.
In the fourth line, print True if S has any lowercase characters. Otherwise, print False.
In the fifth line, print True if S has any uppercase characters. Otherwise, print False.


Sample Input :

qA2

Sample Output :

True
True
True
True
True


Solution :


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# String Validators in Python - HackerRank Solution
# String Validators in Python - HackerRank Solution START
def fun1(s):
    for i in range(len(s)):
        if(s[i].isalnum()):
            return True;
            break;
    return False;
        
def fun2(s):
    for i in range(len(s)):
        if(s[i].isalpha()):
            return True;
            break;
    return False;

def fun3(s):
    for i in range(len(s)):
        if(s[i].isdigit()):
            return True;
            break;
    return False;

def fun4(s):
    for i in range(len(s)):
        if(s[i].islower()):
            return True;
            break;
    return False; 
     
def fun5(s):
    for i in range(len(s)):
        if(s[i].isupper()):
            return True;
            break;
    return False;
 
# String Validators in Python - HackerRank Solution END 
    
if __name__ == '__main__':
    s = raw_input()
    
    # String Validators in Python - HackerRank Solution START
    flagalphanum = fun1(s)
    alphabetical = fun2(s)
    digits = fun3(s)
    lowercase = fun4(s)
    uppercase = fun5(s)
    print(flagalphanum)
    print(alphabetical)
    print(digits)
    print(lowercase)
    print(uppercase)
    # String Validators in Python - HackerRank Solution END




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7 Comments
  • Unknown
    Unknown Thursday, April 01, 2021

    break is not required if using return statement

    Reply
  • Inamul Hassan
    Inamul Hassan Thursday, August 12, 2021

    print(True in list(map(lambda x:x.isalnum(),s)))
    print(True in list(map(lambda x:x.isalpha(),s)))
    print(True in list(map(lambda x:x.isdigit(),s)))
    print(True in list(map(lambda x:x.islower(),s)))
    print(True in list(map(lambda x:x.isupper(),s)))

    Reply
  • Simon's Logic
    Simon's Logic Thursday, January 13, 2022

    def test1(s):
    for i in range(len(s)):
    if s[i].isalnum():
    return True
    return False
    def test2(s):
    for i in range(len(s)):
    if s[i].isalpha():
    return True
    return False
    def test3(s):
    for i in range(len(s)):
    if s[i].isdigit():
    return True
    return False
    def test4(s):
    for i in range(len(s)):
    if s[i].islower():
    return True
    return False
    def test5(s):
    for i in range(len(s)):
    if s[i].isupper():
    return True
    return False

    if __name__ == '__main__':
    s = input()
    result1 = test1(s)
    result2 = test2(s)
    result3 = test3(s)
    result4 = test4(s)
    result5 = test5(s)
    print(result1)
    print(result2)
    print(result3)
    print(result4)
    print(result5)

    Reply
  • Unknown
    Unknown Monday, January 17, 2022

    s = input()
    list_method=['isalnum()','isalpha()','isdigit()','islower()','isupper()']
    for i in list_method:
    for j in s:
    if eval(f"'{j}'.{i}"):
    print(True)
    break

    • Mosaddak
      Mosaddak Tuesday, March 29, 2022

      so nice i tried using eval but not worked
      thank you

    • Mosaddak
      Mosaddak Tuesday, March 29, 2022

      This comment has been removed by the author.

    Reply
  • Mon journal
    Mon journal Sunday, February 13, 2022

    i don't know why you put semicolon ; on python

    Reply
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