itertools.permutations() in Python - HackerRank Solution

itertools.permutations() in Python - HackerRank Solution
itertools.permutations() in Python - HackerRank Solution


Problem


itertools.permutations(iterable[, r])
This tool returns successive r length permutations of elements in an iterable.
If r is not specified or is None, then r defaults to the length of the iterable, and all possible full length permutations are generated.
Permutations are printed in a lexicographic sorted order. So, if the input iterable is sorted, the permutation tuples will be produced in a sorted order.

Sample Code :
>>> from itertools import permutations
>>> print permutations(['1','2','3'])
<itertools.permutations object at 0x02A45210>
>>> 
>>> print list(permutations(['1','2','3']))
[('1', '2', '3'), ('1', '3', '2'), ('2', '1', '3'), ('2', '3', '1'), ('3', '1', '2'), ('3', '2', '1')]
>>> 
>>> print list(permutations(['1','2','3'],2))
[('1', '2'), ('1', '3'), ('2', '1'), ('2', '3'), ('3', '1'), ('3', '2')]
>>>
>>> print list(permutations('abc',3))
[('a', 'b', 'c'), ('a', 'c', 'b'), ('b', 'a', 'c'), ('b', 'c', 'a'), ('c', 'a', 'b'), ('c', 'b', 'a')]

Task :

You are given a string S.
Your task is to print all possible permutations of size k of the string in lexicographic sorted order.



Input Format :

A single line containing the space separated string S and the integer value k.

Constraints :

  • 0 < k <= len(S)

Output Format :

Print the permutations of the string S on separate lines.



Sample Input :

HACK 2

Sample Output :

AC
AH
AK
CA
CH
CK
HA
HC
HK
KA
KC
KH



Solution :


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# itertools.permutations() in Python - Hacker Rank Solution
# Python 3
# itertools.permutations() in Python - Hacker Rank Solution START
from itertools import permutations

s,k = input().split()

words = list(permutations(s,int(k)))
words = sorted(words, reverse=False)
for word in words:
    print(*word,sep='')
# itertools.permutations() in Python - Hacker Rank Solution END





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1 Comments
  • Armin
    Armin Friday, August 05, 2022

    Here my solution:

    from itertools import combinations, combinations_with_replacement

    s, n = input().split()

    for i in combinations_with_replacement(sorted(s), int(n)):
    print("".join(i))

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