Any or All in python - HackerRank Solution
Problem :
any()
This expression returns True if any element of the iterable is true.
If the iterable is empty, it will return False.
Code :
>>> any([1>0,1==0,1<0]) True >>> any([1<0,2<1,3<2]) False
This expression returns True if all of the elements of the iterable are true.
If the iterable is empty, it will return True.
Code :
>>> all(['a'<'b','b'<'c']) True >>> all(['a'<'b','c'<'b']) False
Task :
You are given a space separated list of integers. If all the integers are
positive, then you need to check if any integer is a
palindromic integer.
Input Format :
The second line contains the space separated list of N integers.
Constraints :
- 0 < N < 100
Output Format :
Print True if all the conditions of the problem statement are satisfied.
Otherwise, print False.
Sample Input :
5 12 9 61 5 14
Sample Output :
True
Explanation :
Condition 2: 5 is a palindromic integer.
Hence, the output is True.
Can you solve this challenge in 3 lines of code or less?
There is no penalty for solutions that are correct but have more than 3 lines.
Solution :
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 | # Any or All in python - Hacker Rank Solution # Python 3 # Enter your code here. Read input from STDIN. Print output to STDOUT # Any or All in python - Hacker Rank Solution START def isPositive(i): if i > 0: return True return False def isPalindrome(i): if int(str(i)[::-1]) is i: return True return False N = int(input()) storage = map(int, input().split()) storage = sorted(storage) if all([isPositive(i) for i in storage]): if any([isPalindrome(i) for i in storage]): print("True") else: print("False") else: print("False") # Any or All in python - Hacker Rank Solution END |
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